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3.5x^2-10.5x+2=x^2
We move all terms to the left:
3.5x^2-10.5x+2-(x^2)=0
determiningTheFunctionDomain 3.5x^2-x^2-10.5x+2=0
We add all the numbers together, and all the variables
2.5x^2-10.5x+2=0
a = 2.5; b = -10.5; c = +2;
Δ = b2-4ac
Δ = -10.52-4·2.5·2
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.5)-\sqrt{90.25}}{2*2.5}=\frac{10.5-\sqrt{90.25}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.5)+\sqrt{90.25}}{2*2.5}=\frac{10.5+\sqrt{90.25}}{5} $
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